Microsoft 70-544 : TS: Ms Virtual Earth 6.0, Application Development

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Microsoft TS: Ms Virtual Earth 6.0, Application Development Sample Questions:

1. You are creating a Virtual Earth 6.0 application that retrieves locations from a Microsoft
SQL Server 2005 database. A stored procedure will be used to retrieve only locations that lie within the currently displayed map area. You need to define the boundary within which the locations displayed on the map must lie. How should you define the boundary?

A) the center point of a circle whose radius is equal to the size of the map based on pixel coordinates
B) points represented by the bottom-right and top-left latitude and longitude coordinates
C) points represented by the bottom-right and top-left pixel coordinates
D) the center point of a circle whose radius is equal to the size of the map based on latitude and longitude coordinates

2. You are creating a Web application by using the Virtual Earth 6.0 map control.
A Web page of the application provides links to a number of pre-defined locations. The application must meet the following requirements:
The links can be shared.
The links are encoded with map properties.
Users can copy the links to the Windows clipboard.
You need to write code to meet the requirements.
Which code fragment should you use?

A) <button id="Link" onclick="location.replace(' http:
//www.mymappingsite.com/mymappage.aspx?40.689167&-74.04472&16&h');"> Liberty
< /button>
B) <code id="Link"
onclick="window.open(location.protocol+location.pathname+'?40.689167&-
7 4.04472&16&h');"> Liberty </code>
C) <a id="Link" href="http: //www.mymappingsite.com/mymappage.aspx?40.689167&-
74.04472&16&h">Liberty</a>
D) <address id="Link"
onclick="location.replace(location.protocol+location.pathname+'?40.689167&-
74.04472&16&h');"> Liberty </address>

3. You are creating a Web application. The opening page of the application pre-loads a fixed map that displays your office location. You need to ensure that the map displays a bird's eye view of your office location. You also need to ensure that the view remains fixed.
Which code segment should you use?

A) map.LoadMap(new VELatLong(40.689167,-74.04472),14,'o' ,true,
VEMapMode.Mode3D, false);
B) map.LoadMap(new VELatLong(40.689167,-74.04472),14,'o' ,false,
VEMapMode.Mode2D, false);
C) map.LoadMap(new VELatLong(40.689167,-74.04472),14,'h' ,false,
VEMapMode.Mode3D, false);
D) map.LoadMap(new VELatLong(40.689167,-74.04472),14,'o' ,true,
VEMapMode.Mode2D, false);

4. You are creating a Virtual Earth 6.0 application to be viewed by using Microsoft Internet
Explorer. The Web pages of the application contain maps.
The head section of the Web pages contains the following code fragment.
< script type="text/javascript">
var map = null;
function GetMap(){
map = new VEMap('Map');
map.LoadMap();
ResizeMap();
}
< /script> <style type="text/css">
html, body{ overflow:hidden; }
< /style>
The body section of the Web pages contains the following code fragment.
< body onload="GetMap();">
< div id='Map' style="position:relative; width:400px;
height:400px;"></div>
< /body>
You need to resize the maps on the Web pages so that they exactly fit into the dimensions of the available browser area.
Which code segment should you use?

A) function ResizeMap(){ var height = screen.height; var width = screen.width; map.Resize(width, height); }
B) function ResizeMap(){ var height = document.body.offsetHeight; var width = document.body.offsetWidth; map.Resize(width, height); }
C) function ResizeMap(){ document.getElementById('Map').style.width =
screen.availWidth; document.getElementById('Map').style.height = screen.availHeight; }
D) function ResizeMap(){ document.getElementById('Map').style.width = "100%"; document.getElementById('Map').style.height = "100%"; }

5. You are integrating third-party data into a Virtual Earth 6.0 application. The data that is retrieved from the third party is stored in an array named Results. The Results array is stored inside a Web handler. The data is stored in the following format.
R esults[0]["name"] = "A. Datum Corporation";
Results[0]["address"] = " 123 Main St. , New York , NY ";
Results[0]["latitude"] = "40.123";
Results[0]["longitude"] = "-70.456";
Results[0]["thumbnail"] = "http://www.adatum.com/st3465.jpg";
...
Results[x]
The Web handler uses the GeoRSSFeed class to accept items of type GeoRSSItem. The class contains the ToString() method that writes the GeoRSS feed to a string.
The Web handler GeoRSS integration is defined by the following code segment. (Line numbers are included for reference only.)
0 1 GeoRSSFeed feed = new GeoRSSFeed();
0 2 GeoRSSItem curItem;
0 3 for (int i = 0; i < Results.length; i++){
0 4 curItem = new GeoRSSItem();
0 5 ...
0 6 feed.Add(curItem);
0 7 }
0 8 // Write feed to HTTP Response
0 9 context.Write(feed.ToString());
The Web handler uses the GeoRSSItem class that contains the following code segment.
(Line numbers are included for reference only.)
1 0 public class GeoRSSItem {
1 1 public Dictionary < string, string > elements;
1 2 publ ic GeoRSSItem(){
1 3 elements = Dictionary < string, string > ();
1 4 }
1 5 public void Add(string pName, string pValue){
1 6 elements.Add(pName, pValue);
1 7 }
1 8 }
You need to encode the data inside the Results array into the GeoRSS format.
Which code segment should you insert at line 05?

A) curItem.Add("name", Results[i]["name"]);
curItem.Add("address", string.Format("{0}|{1}", _
Results[i]["address"], _
Results[i]["thumbnail"]);
curItem.Add("latitude", Results[i]["latitude"]);
curItem.Add("longitude", Results[i]["longitude"]);
B) curItem.Add("title", Results[i]["name"]); curItem.Add("description", Results[i]["address"]); curItem.Add("latitude", Results[i]["latitude"]); curItem.Add("longitude",
Results[i]["longitude"]); curItem.Add("icon", Results[i]["thumbnail"]);
C) String [] keys = Results[i].Keys; String curKey; For (int i = 0; i < keys.length; i++){ curKey = keys[i]; curItem.Add(curKey, Results[i][curKey]); }
D) curItem.Add("title", Results[i]["name"]); curItem.Add("description", string.Format("{0}|{1}",
_ Results[i]["address"], _ Results[i]["thumbnail"]); curItem.Add("latitude",
Results[i]["latitude"]); cur Item.Add("longitude", Results[i]["longitude"]);

Solutions: